Question Asked in SBI PO Prelims 8th July 2018 : All Shifts Pdf Download

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    Memory Based Question Asked in SBI PO Prelims 2018 Download Pdf

    Hello Aspirants, as we know that today was second day of sbi PO prelims exam. So we are providing Memory Based questions asked in SBI PO exam pattern held on 8th July 2018. Here we will are providing you the section-wise Memory Based Questions. We are updating one by one all the questions stay tuned and book mark this page.

    SBI PO Questions Asked on 8th July 2018 1st Shift Prelims Exam

    #1 SBI PO English Questions Asked on 8th July Paper

    • Reading Comprehension - The passage asked was based on the topic of ‘ Unemployment Rate in America ‘. There were 2 questions of synonyms & antonyms.
    • Cloze Test – The cloze test was related to the topic of ‘Economy’.Old pattern cloze test was asked.
    • Find the correct sentence – In this among the given sentences , students were required to find the correct one.
    • Phrase Replacement – In this question, a part of the sentence was bold. Among the given options, candidates needed to find the correct replacement for the bold part.
    • Sentence Rearrangement – Sentences were divided in to different parts. Students were required to arrange it in a specific order.

    #2 SBI PO Quant Question Asked in 8th July Paper

    • Number Series – Missing number series questions were asked. The questions were easy. Following number series questions were asked –
      1. 200, 101, 102, 154 ?
      2. 5000, 1000, 400, 320, ?,
      3. 163844, 9, 17, 35, ?,
      4. 1392, 15, 59, 117, 116 ?
      5. 26, 138, 29, 142, 34, 148 ?
    • Data Interpretation – 2 DI questions were asked. 
    1. One was based on data of 2 pie charts. The question was based on number of vehicles.
    2. Second DI was based on Sales and expenses. In this a Bar Graph was given.
    • Number Series – Missing number series questions were asked. The questions were slightly tricky.
    • Simplification/ Approximation - The questions were based on simple rules of BODMAS. 
    • Quadratic Equation – The factors were easily recognizable. Old pattern and easy level questions were asked.
    • Quantity based – In this topic, Quantity I and quantity II were provided. After a suitable comparison, students were required to find the correct option. Questions from different miscellaneous topics were asked.
    • Miscellaneous Questions – The questions were asked from the topics of Percentage, Profit and loss, partnership, time & work, mixture, time & distance etc.

    #3 SBI PO Reasoning Question Asked in 8th July Paper

    • Puzzles and Seating Arrangement – 
    1. One Floor based puzzle was asked. In this 4 floors were given. 3 persons were sitting on each floor.
    2. One linear seating arrangement was asked
    3. One scheduling based puzzle was asked.
    4. One month based puzzle was asked
    • Coding- decoding – Old pattern questions were asked. 

    Previous Shifts Questions Below

    Set (1-5) Read the following information and answers the given questions.

    In a college, three programming languages are taught. Out of 1200 students, each one is required to study at least one of the three languages which are BASIC, COBAL and C. 40 students study all the three languages. 404 students study only C, 222 students study only BASIC, 500 students study COBAL, 114 students study both C and BASIC and 388 students study only COBAL.

    1. How many students study two programming languages only such that at least one of the two languages is COBAL?

    (A) 36

    (B) 72

    (C) 48

    (D) 60

    (E) 80

    2. What is the number of students who study exactly two languages?

    (A) 146

    (B) 126

    (C) 136

    (D) 156

    (E) 132

    3. If the number of students study C language is 554, then what is the number of students study BASIC language?

    (A) 348

    (B) 372

    (C) 336

    (D) 308

    (E) 318

    4. If the number of students study BASIC language is 384, then what is the number of students study both COBOL and C languages?

    (A) 24

    (B) 36

    (C) 72

    (D) 48

    (E) 64

    5. What is the total number of students study C and BASIC languages?

    (A) 720

    (B) 772

    (C) 812

    (D) 782

    (E) 834


    Set (6 – 10) Read the following information and answers the given questions.

    Dhoni and kohli study in the same school and go to school by walk. Dhoni starts from his house at 8.20 a.m. usually. On Tuesday he walked at 6 km/hr and was late by 8 minutes. On Wednesday he increased his speed to 8 km/hr and reached 8 minutes early. Kholi starts from his house at 8.10 a.m. usually. On Tuesday, he walked at 6.5 km/hr and was late by 12 minutes. On Wednesday he increased his speed to 8 km/hr and reached 6 minutes early.

    6. What is the distance from Dhoni house to School?

    (A) 6.4 km

    (B) 7.2 km

    (C) 5.6 km

    (D) 7.6 km

    (E) None of these

    7. If both Dhoni and Kohli reached the school at the right time on Thursday, what were their walking speeds respectively?

    (A) 48/7 km/hr, 52/7 km/hr

    (B) 49/8 km/hr, 27/4 km/hr

    (C) 57/7 km/hr, 31/5 km/hr

    (D) 61/9 km/hr, 33/7

    (E) None of these

    8. What is the distance from kohli house to school?

    (A) 8 km

    (B) 9.6 km

    (C) 9.8 km

    (D) 10.4 km

    (E) 10.2 km


    SET (9-11) Read the following information and answers the questions.

    There are four mixtures of water and milk.

    Mixture A contains water and milk in the ratio 5: 4

    Mixture B contains water and milk in the ratio 1: 5

    Mixture C contains water and milk in the ratio 4:5

    Mixture B and C mixed in 1: 3 result in mixture D.

    9. What is the ratio of water and milk in mixture D?

    (A) 3:5

    (B) 3:4

    (C) 4: 3

    (D) 5: 3

    (E) 2: 3

    10. In what ratio should mixture A and B be mixed in order to get mixture C?

    (A) 2:3

    (B) 3: 4

    (C) 1:5

    (D) 5: 2

    (E) 2: 5

    11. In what ratio should mixtures A and D be mixed so that the volumes of water and milk are equal in the resultant mixture?

    (A) 4: 7

    (B) 7: 4

    (C) 9: 4

    (D) 6:1

    (E) 1:2


    Set (12 – 16) Study the following passage and answers the questions.

    A certain number of students are interested in different activities like Singing, painting and dancing. 240 of them are interested in only painting. The total number of students who are interested in both painting and singing is 6/5 of the number of students who are interested in only painting. 5/8 of the number of students interested in both painting and singing are interested in all the three activities. The number of students interested in both singing and dancing but not painting is the average of the number of students who are interested in only painting and the number of students who are interested in all the three activities. The number of students who are interested in only dancing is 30% more than the number of students who are interested in both singing and dancing but not painting. The number of students interested in singing is same as the number of students interested in dancing. The number of students interested in only singing is half the number of students interested in more than one activity.

    12. How many students like any of the given activities?

    (A) 1472

    (B) 1498

    (C) 1512

    (D) 1523

    (E) 1533

    13. What percentage of the total number of students likes all the three activities?

    (A) 12.23%

    (B) 11.90%

    (C) 13.33%

    (D) 16.67%

    (E) 14.28%

    14. What is the difference between the number of people who like dancing but not painting and the number of people who like painting but not dancing?

    (A) 145

    (B) 125

    (C) 175

    (D) 135

    (E) 150

    15. How many students like exactly two activities?

    (A) 477

    (B) 457

    (C) 468

    (D) 448

    (E) 486

    16. How many students like only Dancing?

    (A) 273

    (B) 265

    (C) 257

    (D) 270

    (E) 250

    SET (17 – 20) Study the following paragraph and answer the questions.

    In Chennai Anna University, the first year is a foundation program for all the students after which in second year the students can-opt for their major subject. In 2015, only 80% of the students passed the first year examination and all of those who passed joined in the second year. In 2015, only 20% of students of first year who passed the first year examination joined physical sciences, 30% joined the Arts stream, 40% joined commerce stream while others joined computer stream. Apart from those, some students from other universities who passed their first year also joined Chennai Anna University. Such students were 30% of the number of first year students from Chennai Anna University who passed 2015 examination. The number of students from other universities across physical sciences, Arts, commerce and computer streams are joined in Chennai Anna University were in ratio 1: 3: 4: 2 respectively. In 2015, the number of students in Arts stream in Chennai Anna University in second year was 780.

    17. In 2015, what percent of science stream students in second year in Chennai Anna University were first year science stream students who pass-outs from Chennai Anna University only? (Approximately)

    (A) 87%

    (B) 83%

    (C) 92%

    (D) 77%

    (E) 73%

    18. What is the total number of students promoted to second year?

    (A) 2500

    (B) 2250

    (C) 2000

    (D) 1500

    (E) 1750

    19. What is the total number of students studying in Chennai Anna University in second year?

    (A) 2000

    (B) 2600

    (C) 2300

    (D) 2700

    (E) 2400

    20. What was the number of students in second year commerce stream in Chennai Anna University in 2015?

    (A) 1040

    (B) 1080

    (C) 1050

    (D) 1150

    (E) 1200

    21. What is the number of students from other universities joining Chennai Anna University in 2015?

    (A) 500

    (B) 600

    (C) 800

    (D) 400

    (E) 1000


    Aspirants can check the answers for the above Questions from the below given ones. 


    1. (b) 

    image15Only two languages (One is COBOL)= 1200- (404+388+222+40+74)= 72


    2. (a) 

    image15

    COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72

    Exactly any two languages only = = 72+74 = 146


     

    3. ( b ) 

    image15

    COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72

    C language= 404+74+40+(72-COBOL language and BASIC only)=554

    Therefore, COBOL+BASIC =( 404+74+40+72)-554=36

    Required total = 222+74+40+36 = 372


    4. (e) 

     

    BASIC language = 222+74+40+(BASIC and COBOL only)=384

    BASIC and COBOL only=384-(222+74+40)=48

    Therefore, COBOL and C only=72(BASIC and COBOL only + COBOL and C only) – 48=24

    Both COBOL and C = 40+24=64


    5. (c) 

    image15

    Number of students study C and BASIC language = Total-COBOL only

    =1200-388=812


    6. (a)

    Dhoni:

    Let the distance between his house and school be Y km

    Time taken when he walks at 6 km/hr = Y/6

    Time taken when he walks at 8 km/hr = Y/8

    In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.

    So, we have, 

    Y = 6.4 km


    7. (a) 

    Dhoni:

    Let the distance between his house and school be Y km

    Time taken when he walks at 6 km/hr = Y/6

    Time taken when he walks at 8 km/hr = Y/8

    In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.

    So, we have, 

    Y = 6.4 km

    Dhoni needs to cover 6.4 km

    In 1st case he walks at 6 km/hr

    Required time = = 64 minutes

    Therefore, 8 minutes late, = 64-8 = 56 minutes.

    Required speed =

    Kohli:

    Let the distance between his house and school be Z km

    Time taken when he walks at 6.5 km/hr = Z/6.5

    Time taken when he walks at 8 km/hr = Z/8

    In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.

    So, we have, 

    Z = 10.4 km

    In 2nd case he walks at 8 km/hr

    Required time == 78 minutes

    Therefore, 6 minutes late, = 78+6 = 84 minutes.

    Required speed = 


    8. (d) 

    Kohli:

    Let the distance between his house and school be Z km

    Time taken when he walks at 6.5 km/hr = Z/6.5

    Time taken when he walks at 8 km/hr = Z/8

    In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.

    So, we have, 

    Z = 10.4 km


    9. (a) 

    water: milk = 4: 5

    Mixture D is obtaining by mixing B and C in the ratio 1: 3

    Let x litres of B and 3x litres of C be mixed.

     


     

    10. ( d) 

    water: milk = 4: 5

    Required ratio= 5:2


    11. (c) 

    water: milk = 4: 5

    Mixture D is obtaining by mixing B and C in the ratio 1: 3

    Let x litres of B and 3x litres of C be mixed.

     

     

    Required ratio= (1/8 ) : (1/18) =18:8=9:4


    12. (c) 

    The total number of students who are interested in both painting and singing =240×(6/5)=288

    The number of students interested in all the three activities = (5/8)×288= 180

    Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

    The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

    The number of students who are interested in only dancing = 210×1.3= 273

    Let, the number of students interested in only singing = x

    Let, the number of students interested in both dancing and painting but not singing = y

    108+180+210+x = 210+180+y+273

    x-y = 165

    Also,

    108+180+y+ 210 = 2x

    498+y=2x

    Y = 2x-498

    x-2x-498 = 165

    498-165 = x

    333 = x

    Y = 168

    Required total = 240+108+168+180+210+273+333 = 1512


    13. (b) 

    The total number of students who are interested in both painting and singing =240 × (6/5)=288

    The number of students interested in all the three activities =  (5/8) × 288= 180

    Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

    The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

    The number of students who are interested in only dancing = 210×1.3= 273

    Let, the number of students interested in only singing = x

    Let, the number of students interested in both dancing and painting but not singing = y

    108+180+210+x = 210+180+y+273

    x-y = 165

    Also,

    108+180+y+ 210 = 2x

    498+y=2x

    Y = 2x-498

    x-2x-498 = 165

    498-165 = x

    333 = x

    Y = 168

    Required % =


    14. (d) 

    The total number of students who are interested in both painting and singing =240× ( 6/5)=288

    The number of students interested in all the three activities =( 5/8 ) ×288= 180

    Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

    The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

    The number of students who are interested in only dancing = 210×1.3= 273

    Let, the number of students interested in only singing = x

    Let, the number of students interested in both dancing and painting but not singing = y

    108+180+210+x = 210+180+y+273

    x-y = 165

    Also,

    108+180+y+ 210 = 2x

    498+y=2x

    Y = 2x-498

    x-2x-498 = 165

    498-165 = x

    333 = x

    Y = 168

    Required difference = 273+210-(240+108)=135


    15. (e) 

    The total number of students who are interested in both painting and singing =240× (6/5)=288

    The number of students interested in all the three activities = (5/8) ×288= 180

    Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

    The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

    The number of students who are interested in only dancing = 210×1.3= 273

    Let, the number of students interested in only singing = x

    Let, the number of students interested in both dancing and painting but not singing = y

    108+180+210+x = 210+180+y+273

    x-y = 165

    Also,

    108+180+y+ 210 = 2x

    498+y=2x

    Y = 2x-498

    x-2x-498 = 165

    498-165 = x

    333 = x

    Y = 168

    Required total = 108+168+210 = 486


    16. (a)

    The total number of students who are interested in both painting and singing =240× (6/5)=288

    The number of students interested in all the three activities = (5/8) ×288= 180

    Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

    The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

    The number of students who are interested in only dancing = 210×1.3= 273

    Let, the number of students interested in only singing = x

    Let, the number of students interested in both dancing and painting but not singing = y

    108+180+210+x = 210+180+y+273

    x-y = 165

    Also,

    108+180+y+ 210 = 2x

    498+y=2x

    Y = 2x-498

    x-2x-498 = 165

    498-165 = x

    333 = x

    Y = 168

    Required total = 273


    17. (a)

    Let us assume the total number of first year students in Chennai Anna university be X

    Then, as per data, number of students who passed in first year = 0.8X

    Students in physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

    Total number of students from other universities = 30% of 0.8X = 0.24 X

    Ratio of students from other universities in different streams is

    Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

    Given that number of students in arts stream = 780

    Therefore,

    0.072X+ 0.24X = 780

    X= 2500

    Hence, total number of students in first year = 2500

    Total students in promoted to second year = 2000

    Students from other Universities joining Chennai Anna University = 0.24X = 600

    Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

    Total science students in Chennai Anna University = 0.16x+0.024x = 460

    First year pass- outs of Chennai Anna University joining science stream = 0.16X = 400

    Required % = (400/460)×100=87%


    18. (c)

    Let us assume the total number of first year students in Chennai Anna university be X

    Then, as per data, number of students who passed in first year = 0.8X

    Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

    Total number of students from other universities = 30% of 0.8X = 0.24 X

    Ratio of students from other universities in different streams is

    Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

    Given that number of students in arts stream = 780

    Therefore,

    0.072X+ 0.24X = 780

    X= 2500

    Hence, total number of students in first year = 2500

    Total students in Anna University promoted to second year = 2000


    19. (b) 

    Let us assume the total number of first year students in Chennai Anna university be X

    Then, as per data, number of students who passed in first year = 0.7X

    Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

    Total number of students from other universities = 30% of 0.8X = 0.24 X

    Ratio of students from other universities in different streams is

    Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

    Given that number of students in arts stream = 780

    Therefore,

    0.072X+ 0.24X = 780

    X= 2500

    Hence, total number of students in first year = 2500

    Total students in promoted to second year = 2000

    Students from other Universities joining Chennai Anna University = 0.24X = 600

    Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600


    20. (a) 

    Let us assume the total number of first year students in Chennai Anna university be X

    Then, as per data, number of students who passed in first year = 0.8X

    Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

    Total number of students from other universities = 30% of 0.8X = 0.24 X

    Ratio of students from other universities in different streams is

    Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

    Given that number of students in arts stream = 780

    Therefore,

    0.072X+ 0.24X = 780

    X= 2500

    Hence, total number of students in first year = 2500

    Total students in Anna University promoted to second year = 2000

    Students from other Universities joining Chennai Anna University = 0.24X = 600

    Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

    Total number of students in commerce stream in 2015 = 0.32X+0.096X = 0.416X = 1040


    21. ( b )

    Let us assume the total number of first year students in Chennai Anna university be X

    Then, as per data, number of students who passed in first year = 0.8X

    Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

    Total number of students from other universities = 30% of 0.8X = 0.24 X

    Ratio of students from other universities in different streams is

    Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.024X

    Given that number of students in arts stream = 780

    Therefore,

    0.072X+ 0.24X = 780

    X= 2500

    Hence, total number of students in first year = 2500

    Total students in promoted to second year = 2000

    Students from other Universities joining Chennai Anna University = 0.24X = 600

    Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

    SBI PO Prelims Exam Analysis & Review 2018 8th July (All Shifts)

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